⛪ Church of All Saints (Keokuk, Iowa)
United States · Americas · 40.40°N, 91.39°W
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Quick facts
| Country | United States |
|---|---|
| Continent / region | Americas |
| Coordinates (approx.) | 40.40°N, 91.39°W · view on map |
| Distance to the equator | 4,497 km north of it |
| Solar time | UTC-6 — read from longitude, so it is the sky's clock rather than the government's |
| Sun today (UTC) | Rises 12:42, sets 22:57 — 10 h 15 min of daylight |
Church of All Saints (Keokuk, Iowa) is located in United States, in Americas.
Closest churches
- St. John's Episcopal Church (Keokuk, Iowa) — 0.8 km away
- St. Barnabas Episcopal Church (Montrose, Iowa) — 15 km away
- St. Luke's Episcopal Church (Fort Madison, Iowa) — 27 km away
- Denmark Congregational United Church of Christ — 39 km away
- First Presbyterian Church (La Grange, Missouri) — 40 km away
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